X=1/2,y=-1,z=2,6x(y^2z)

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Solution for X=1/2,y=-1,z=2,6x(y^2z) equation: 


1;3;2;3;5;2

7;9;8;9;5;0

1;8;5;8;6;0

1;7;5;7;3;0

1;7;5;7;3;3

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